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object-in-enumerable
Gives the more-readable `foo.in?(some_list)` rather than having to revert to the more backward `some_list.include?(foo)`.
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Ranking: 121,634 of 192,505
Downloads: 5,719
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Ranking: 90,203 of 192,483
Downloads: 1
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| # | Gravatar | Handle |
|---|---|---|
| 1 | pbyrne |